1. Distance and Displacement - NEET Physics Chapterwise MCQs & PYQs

NEET 1. Distance and Displacement MCQs & PYQs

Question 11:

easy

The magnitude of vectors \(\vec{A},\vec{B}\) and \(\vec{C}\) are 3, 4 and 5 units respectively. If \(\vec{A} + \vec{B} = \vec{C}\) , the angle between \(\vec{A}\) and \(\vec{B}\) is:

(1988)

Given \(|\vec{A}|=3, |\vec{B}|=4, |\vec{C}|=5\) and \(\vec{A} + \vec{B} = \vec{C}\). Squaring both sides: \(|\vec{A} + \vec{B}|^2 = |\vec{C}|^2\). \(|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}|cos\theta = |\vec{C}|^2\). Substituting values: \(3^2 + 4^2 + 2(3)(4)cos\theta = 5^2\) which gives \(9 + 16 + 24cos\theta = 25\). Thus, \(24cos\theta = 0\) and \(\theta = \pi/2\).

Question 12:

easy

Given below are two statements one is labelled as assertion (A) and reason (R)


Assertion: The length of actual path travelled by a body in given time interval is always equal to displacement.


Reason: If displacement is zero, then body is either at rest or it has returned to initial position.


Choose the correct option.

Distance (actual path length) is greater than or equal to displacement magnitude, so the assertion is false. If displacement is zero, the body either remained at rest or returned to its starting point, making the reason true.