Current Electricity - NEET Physics Chapterwise MCQs & PYQs
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NEET Current Electricity MCQs & PYQs
Practice NEET Current Electricity Questions
Question 131:
easy
Assertion (A): The resistivity of a semiconductor decreases with increase in temperature.
Reason (R): In a conductor, the rate of collisions between free electrons and ions increases with increase of temperature.
Assertion (A) is true. Increased temperature in semiconductors generates more charge carriers, decreasing resistivity. Reason (R) is also true, as thermal vibrations increase electron-ion collisions in conductors, increasing resistivity. However, (R) explains conductors, not semiconductors, so it's not the correct explanation for (A).
Assertion (A): Terminal potential difference of a cell is always less than its emf.
Reason (R): Potential drop across internal resistance of cell increases terminal potential difference.
Assertion (A) is false. The terminal potential difference \( V \) is equal to emf \( E \) when no current is drawn (open circuit) and can be greater than \( E \) during charging. Reason (R) is false. The potential drop across internal resistance (\( Ir \)) actually decreases the terminal potential difference (\( V = E - Ir \) for discharging).
Reason (R): The emf of a dry cell is proportional to its size.
The electromotive force (EMF) of a cell depends only on the nature of the electrodes and electrolyte, not its size. Size affects internal resistance and current capacity. Both assertion and reason are incorrect.
Assertion (A): A car battery is of \(12\text{ V}\). Eight dry cells of \(1.5\text{ V}\) connected in series can give \(12\text{ V}\). Still such cells are not used in starting a car.
Reason (R): It is easier to start a car engine on a warm day than on a rainy day.
Assertion (A) is true: \(8 times 1.5\text{ V} = 12\text{ V}\). Dry cells have high internal resistance and cannot provide the high current needed to start a car. Reason (R) is also true, as engine oil is less viscous on a warm day. However, (R) does not explain (A).
Assertion (A): When identical cells are connected in parallel to the external load, the effective emf increases.
Reason (R): All the cells will be sending unequal current to the external load in the same direction.
When identical cells are connected in parallel, the effective EMF remains the same as that of a single cell, while the current capacity increases. Thus, Assertion (A) is false. For identical cells, current distribution should be equal. Thus, Reason (R) is also false.
Assertion (A): In a balanced Wheatstone bridge, the current through cell depends on resistance of galvanometer.
Reason (R): At balanced condition current through galvanometer is non-zero.
In a balanced Wheatstone bridge, the current through the galvanometer is zero. Hence, the galvanometer's resistance does not affect the equivalent resistance of the bridge and thus the current drawn from the cell. Both Assertion (A) and Reason (R) are false.
Assertion (A): If an observer is moving with drift speed of electrons in direction opposite to current, observer will not experience any magnetic field.
Reason (R): In the frame of observer charged particles in conductor are at rest.
If an observer moves with the electron drift speed (in the direction of electron flow), electrons are at rest relative to them. However, the positive lattice ions, which were stationary in the conductor's frame, are now moving. This motion of positive ions constitutes a current and produces a magnetic field.
Thus, (A) is false. Also, in this frame, only electrons are at rest, while positive ions are moving, so (R) is false.
On the basis of electrical conductivity, which one of the following material has the smallest resistivity?
Silver is a metal with a very high electrical conductivity, which means it has the lowest resistivity among the given options (glass is an insulator, while silicon and germanium are semiconductors).
A certain wire \(A\) has resistance \(81 \Omega\). The resistance of another wire \(B\) of same material and equal length but of diameter thrice the diameter of \(A\) will be
Using \(R = \rho \frac{l}{A} = \rho \frac{l}{\pi (d/2)^2} \propto \frac{1}{d^2}\). Since diameter \(d_B = 3d_A\), the resistance \(R_B = \frac{R_A}{3^2} = \frac{81}{9} = 9 \Omega\).
A copper wire of radius 1 mm contains \(10^{22}\) free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron \(= 1.6 \times 10^{-19} \text{C}\))
Using \(I = n e A v_d ⇒ v_d = \frac{I}{n e \pi r^2}\). Substituting values, we get \(v_d = \frac{10}{10^{22} \times 1.6 \times 10^{-19} \times \pi \times (10^{-3})^2} = \frac{6.25}{\pi} \times 10^3 \text{ms}^{-1}\).