Ground to Ground Projectile: Practice Problem & Solution
Two particles A and B are projected from ground at an angle of \( 30^\circ \) with the horizontal with velocity \( 20\text{ m/s} \) and \( 40\text{ m/s} \) respectively. The maximum height and time of flight are both greater for which particle?
Solution Explained:
To solve this problem, we apply the core principles of Ground to Ground Projectile. Understanding the underlying formula is key to arriving at the correct answer below:
Maximum height \( H \propto u^2 \) and Time of flight \( T \propto u \) for a given angle. Since particle B has a larger initial velocity, both parameters are greater for B.
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