Average Speed and Velocity: Practice Problem & Solution
A car covers the first half of the distance between two places at \(40 \text{ km/h}\) and another half at \(60 \text{ km/h}\). The average speed of the car is: (1990)
Solution Explained:
To solve this problem, we apply the core principles of Average Speed and Velocity. Understanding the underlying formula is key to arriving at the correct answer below:
For equal distances, average speed \(v_{avg} = \frac{2v_1 v_2}{v_1 + v_2}\). Given \(v_1 = 40 \text{ km/h}\) and \(v_2 = 60 \text{ km/h}\). So, \(v_{avg} = \frac{2 \times 40 \times 60}{40 + 60} = \frac{4800}{100} = 48 \text{ km/h}\).
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