Parallel Plate Capacitor: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:

If the plates are connected in series, the total capacitance \( C_{\text{eq}} \) of \( n-1 \) capacitors is given by \( \frac{1}{C_{\text{eq}}} = \frac{n-1}{C} \), which yields \( C_{\text{eq}} = \frac{C}{n-1} \).