Capacitor With Dielectrics: Practice Problem & Solution
A capacitor remains connected to a battery, a dielectric slab is slipped between the plates. The energy will increase due to
Solution Explained:
To solve this problem, we apply the core principles of Capacitor With Dielectrics. Understanding the underlying formula is key to arriving at the correct answer below:
As the capacitor remains connected to the battery, the potential difference \(V\) remains constant. The stored energy is \(U = \frac{1}{2} C V^2\). Since slipping a dielectric slab increases the capacitance \(C\), the energy increases correspondingly.
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