Parallel Plate Capacitor Force – Rankers Physics

Parallel Plate Capacitor: Practice Problem & Solution

Assertion (A): Two protons placed at different distances, between the plates of a parallel plate capacitor experience the same force. Reason (R): The electric field between the plates of parallel plate capacitor is constant.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true because the electric field (E) in a parallel plate capacitor is uniform. The force on a proton (q) is F = qE , which is constant. Reason (R) is true as the electric field between plates of an ideal parallel plate capacitor is constant. (R) correctly explains (A).

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Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. An air filled parallel plate capacitor charged to potential \(V_1\) is connected to uncharged parallel plate capacitor having dielectric constant \(k\). The common potential of both is \(V_2\). What is the value of \(k\)?
2. Assertion (A): A capacitor of a certain capacity, whenever charged, will always store the same amount of charge. Reason (R): A definite capacity implies always a same definite value of charge.  
3. Three capacitors each of capacity $4 \mu F$ are to be connected in such a way that the effective capacitance is $6 \mu F$. This can be done by: (2003)
4. A parallel plate capacitor has area of each plate as \(A\), the separation between the plates as \(d\) and it is charged to potential \(V\), and then disconnected from the battery. If a dielectric slab, completely filling the capacitor is introduced, how much work will be done in doing so
5. A capacitor is connected to a battery. The electric energy stored in it is \(E\). If the separation between the plates is doubled, what will be the energy on the capacitor?