Capacitor Charge Storage – Rankers Physics

Parallel Plate Capacitor: Practice Problem & Solution

Assertion (A): A capacitor of a certain capacity, whenever charged, will always store the same amount of charge. Reason (R): A definite capacity implies always a same definite value of charge.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:

A: False. The charge stored by a capacitor is \(Q = CV\). For a given capacitance \(C\), the charge \(Q\) depends on the applied voltage \(V\), which can vary.\nR: False. A definite capacity \(C\) does not imply a definite charge \(Q\), as \(Q\) is also proportional to the voltage \(V\) across the capacitor, which can be varied.\nTherefore, both (A) and (R) are false.

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