Alternating Current: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

For an ideal transformer, input power equals output power: $P_p = P_s$.
The output power (power of the lamp) is $P_s = 44 W$.
Primary voltage is $V_p = 220 V$, so $V_p I_p = 44$.
$I_p = \frac{44}{220} = 0.2 A$.