Rankers Physics

Alternating Current: Practice Problem & Solution

9. A capacitor of capacity C and reactance X if capacitance and frequency become double then reactance will be: (2001)
$4X$
$\frac{X}{2}$
$\frac{X}{4}$
$2X$

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

Capacitive reactance is $X = \frac{1}{2\pi f C}$. When capacitance becomes $2C$ and frequency becomes $2f$, the new reactance is $X' = \frac{1}{2\pi(2f)(2C)} = \frac{1}{4(2\pi f C)} = \frac{X}{4}$.

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