Work Done by Constant and Variable Forces: Practice Problem & Solution
A body, constrained to move in \(y\)-direction, is subjected to a force given by \(F = (-2\hat{i} + 15\hat{j} + 6\hat{k})\text{ N})\). The work done by this force in moving the body through a distance of \(10\hat{j}\text{ m})\) along \(y\)-axis, is: (1994)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Work Done by Constant and Variable Forces. Understanding the underlying formula is key to arriving at the correct answer below:
Force \(F = (-2hat{i} + 15hat{j} + 6hat{k})\). Displacement \(dr = 10hat{j}\text{ m})\). Work \(W = F cdot dr\). \(W = (15)(10) = 150\text{ J}\).
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