Efficiency of Pulley System – Rankers Physics

Principal of Conservation of Energy: Practice Problem & Solution

250 N force is required to raise 75 kg mass from a pulley. If rope is pulled 12 m then the load is lifted to 3 m, the efficiency of pulley system will be: (2001)
$25\%$
$33.3\%$
$75\%$
$90\%$

Solution Explained:

To solve this problem, we apply the core principles of Principal of Conservation of Energy. Understanding the underlying formula is key to arriving at the correct answer below:

Efficiency $\eta = \frac{\text{Work output}}{\text{Work input}} = \frac{mgh}{F \cdot d} = \frac{75 \times 10 \times 3}{250 \times 12} = \frac{3}{4} = 75\%$.

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