Rankers Physics

Standing Wave in String and Organ Pipe: Practice Problem & Solution

A standing wave having 3 nodes and 2 antinodes is formed between $1.21 \text{ \AA}$ distance then the wavelength is: (1998)
$1.21 \text{ \AA}$
$2.42 \text{ \AA}$
$0.605 \text{ \AA}$
$4.84 \text{ \AA}$

Solution Explained:

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

A standing wave with 3 nodes and 2 antinodes corresponds to 2 full loops. The length of one loop is $\lambda/2$. Total distance $L = 2 \times (\lambda/2) = \lambda$. Therefore, the wavelength $\lambda = 1.21 \text{ \AA}$.

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