Rankers Physics

Principle of Superposition, Interference and Beats: Practice Problem & Solution

If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be: (1989)
Increasing by a factor of 2
Decreasing by a factor of 2
Decreasing by a factor of 4
Unchanged

Solution Explained:

To solve this problem, we apply the core principles of Principle of Superposition, Interference and Beats. Understanding the underlying formula is key to arriving at the correct answer below:

Intensity $I \propto A^2 f^2$. New intensity $I' \propto (2A)^2 (f/4)^2 = 4A^2 \times \frac{f^2}{16} = \frac{1}{4} I$. Thus it decreases by a factor of 4.

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