Rankers Physics

Standing Wave in String and Organ Pipe: Practice Problem & Solution

The two nearest harmonics of a tube closed at one end and open at other end are $220 \text{ Hz}$ and $260 \text{ Hz}$. What is the fundamental frequency of the system? (2017-Delhi)
$20 \text{ Hz}$
$30 \text{ Hz}$
$40 \text{ Hz}$
$10 \text{ Hz}$

Solution Explained:

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

For a closed pipe, frequencies are odd multiples of fundamental $f_0$. Difference between successive harmonics is $2f_0 = 260 - 220 = 40 \text{ Hz}$. Thus, $f_0 = 20 \text{ Hz}$.

Leave a Reply

Your email address will not be published. Required fields are marked *