Waves and its Characteristics: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:

Phase difference $\Delta\phi = \frac{2\pi}{\lambda} \Delta x \implies 1.6\pi = \frac{2\pi}{\lambda}(0.4) \implies \lambda = \frac{0.8}{1.6} = 0.5 \text{ m}$. Frequency $f = \frac{v}{\lambda} = \frac{330}{0.5} = 660 \text{ Hz}$.