Rankers Physics

Standing Wave in String and Organ Pipe: Practice Problem & Solution

A wave of frequency $100 \text{ Hz}$ travels along a string towards its fixed end. When this wave travels back, after reflection, a node is formed at a distance of $10 \text{ cm}$ from the fixed end. The speed of the wave (incident and reflected) is: (1994)
$20 \text{ m/s}$
$40 \text{ m/s}$
$5 \text{ m/s}$
$10 \text{ m/s}$

Solution Explained:

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

Distance from fixed end (node) to nearest node is $\frac{\lambda}{2} = 10 \text{ cm} = 0.1 \text{ m}$. Thus $\lambda = 0.2 \text{ m}$. Velocity $v = f\lambda = 100 \times 0.2 = 20 \text{ m/s}$.

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