Rankers Physics

Waves and its Characteristics: Practice Problem & Solution

The equation of a simple harmonic wave is given by $y = 3\sin\frac{\pi}{2}(50t - x)$ where $x$ and $y$ are in metres and $t$ is in seconds. The ratio of maximum particle velocity to the wave velocity is: (2012 Mains)
$2\pi$
$3\pi/2$
$3\pi$
$2/3\pi$

Solution Explained:

To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:

Comparing with $y = A\sin(\omega t - kx)$, we get $A = 3$, $\omega = 25\pi$, and $k = \pi/2$. Maximum particle velocity $v_{p} = A\omega$. Wave velocity $v_{w} = \omega/k$. The ratio is $v_{p}/v_{w} = (A\omega) / (\omega/k) = Ak = 3 \times (\pi/2) = 3\pi/2$.

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