Waves and its Characteristics: Practice Problem & Solution
The displacement of a travelling wave is given by \(y = P \sin \frac{2\pi}{\lambda}(Qt - x)\), where \(t\) is time and \(x\) is distance and \(\lambda\) is wavelength. The linear frequency of the wave is
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:
The wave equation can be rewritten as \(y = P \sin \left(\frac{2\pi Qt}{\lambda} - \frac{2\pi x}{\lambda}\right)\). Here, angular frequency \(omega = \frac{2\pi Q}{\lambda}\). Thus, linear frequency is \(f = \frac{\omega}{2\pi} = \frac{Q}{\lambda}\).
Leave a Reply