Young’s Double Slit Experiment (YDSE) Maxima and Minima Count – Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

Assertion (A): In a Young's double slit experiment if slit separation is slightly greater than (nl) if (n) is integer No. of maxima on screen is (2n + 1) & no of minima is (2n). Reason (R): In Young's double slit experiment path difference at different position are different.
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true. If slit separation (d) is slightly greater than (nlambda), there will be (2n+1) maxima and (2n) minima. Reason (R) is also true as path difference (Delta x = d sintheta) varies with position. However, (R) does not explain the specific count of fringes in (A).

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Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Assertion (A): At the first glance the top surface of a Morpho's butterfly's wing appears a beautiful blue-green. If the wing moves, the colour changes. Reason (R): Different pigments in the wing reflect light at different angles. [Hint: It is due to interference of light rays reflected from different layers of wing.]
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