Miscellaneous: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Miscellaneous. Understanding the underlying formula is key to arriving at the correct answer below:

Using the simplified limit of resolution $\theta = \frac{\lambda}{D}$ (ignoring 1.22 factor to match options), we have $\frac{x}{d} = \frac{\lambda}{D}$, where $x$ is the minimum distance. $x = \frac{5000 \times 10^{-10}}{2 \times 10^{-3}} \times 50 = 2.5 \times 10^{-4} \times 50 = 1.25 \times 10^{-2} m = 1.25 cm$.