Significant Figures in Addition – Rankers Physics

Error Analysis: Practice Problem & Solution

Sum of the numbers \(436.32\text{ g}\), \(227.2\text{ g}\) and \(0.301\text{ g}\) is
663.821 g
663.8 g
6663.82 g
664 g

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Error Analysis. Understanding the underlying formula is key to arriving at the correct answer below:

In addition, the final result must be rounded off to the least number of decimal places of the terms. Here, \(227.2\text{ g}\) has one decimal place, so the sum \(663.821\text{ g}\) is rounded to \(663.8\text{ g}\).

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