Dimensions of `E/G` – Rankers Physics

Dimensions: Practice Problem & Solution

If \(E\) and \(G\) respectively denote energy and gravitational constant, then \(\frac{E}{G}\) has the dimensions of: [2021]
\([M][L]^{-1}[T]^{-1}\)
\([M^{2}][L]^{0}[T]^{0}\)
\([M^{2}][L]^{-2}[T]^{-1}\)
\([M^{2}][L]^{-1}[T]^{0}\)

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Dimensions. Understanding the underlying formula is key to arriving at the correct answer below:

Energy \([E] = ML^2T^{-2}\) and Gravitational Constant \([G] = M^{-1}L^3T^{-2}\). So \([E/G] = M^2L^{-1}T^0\).

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