Thermal Properties of Matter – Rankers Physics

Uncategorized: Practice Problem & Solution

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are $39^\circ\text{W}$ and $239^\circ\text{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^\circ\text{C}$ on the Celsius scale? (2008)
$139^\circ\text{W}$
$78^\circ\text{W}$
$117^\circ\text{W}$
$200^\circ\text{W}$

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Using temperature scale relation: $\frac{W - 39}{239 - 39} = \frac{C - 0}{100 - 0}$. Substituting $C = 39$: $\frac{W - 39}{200} = \frac{39}{100} \Rightarrow W - 39 = 78 \Rightarrow W = 117^\circ\text{W}$.

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