Uncategorized: Practice Problem & Solution
During an isothermal expansion, a confined ideal gas does $150\text{ J}$ of work against its surroundings. This implies that: (2011 Pre)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
In an isothermal process, the temperature remains constant, so the change in internal energy is zero ($\Delta U = 0$). By the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W = 0 + 150\text{ J} = 150\text{ J}$, meaning heat is added.
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