Satellite Acceleration Due to Dust Accretion – Rankers Physics

Uncategorized: Practice Problem & Solution

A satellite in force free space sweeps stationary interplanetary dust at a rate of \( dM/dt = \alpha v \), where \( M \) is mass and \( v \) is the speed of satellite and \( alpha \) is a constant. The acceleration of satellite is: (1995)
\( -\alpha v^2 / (2M) \)
\( -\alpha v^2 \)
\( -2\alpha v^2 / M \)
\( -\alpha v^2 / M \)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

The force on the satellite due to dust accretion is \( F = v_{text{rel}} \frac{dM}{dt} \). Here, the dust is stationary, so \( v_{text{rel}} = -v \). So, \( F = (-v) \frac{dM}{dt} \). From Newton's second law, \( F = M \frac{dv}{dt} \). Thus, \( M \frac{dv}{dt} = -v \frac{dM}{dt} \). Substituting \( \frac{dM}{dt} = \alpha v \), we get \( M \frac{dv}{dt} = -v (\alpha v) = -\alpha v^2 \). Therefore, \( \frac{dv}{dt} = -\frac{\alpha v^2}{M} \).

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