Uncategorized: Practice Problem & Solution
49. Standing waves are produced in $10 \text{ m}$ long stretched string. If the string vibrates in 5 segments and wave velocity is $20 \text{ m/s}$, the frequency is: (1997)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
The string vibrates in 5 segments, so the total length $L = 5 \times (\lambda/2)$. This gives $10 = 2.5 \lambda \implies \lambda = 4 \text{ m}$. Frequency $f = \frac{v}{\lambda} = \frac{20}{4} = 5 \text{ Hz}$.
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