Lift Acceleration from Tension – Rankers Physics

Uncategorized: Practice Problem & Solution

The mass of a lift is \(2000 text{ kg}\). When the tension in the supporting cable is \(28000 text{ N}\), then its acceleration is: (2009)
\(4 text{ m/s}^2\) upwards.
\(4 text{ m/s}^2\) downwards.
\(14 text{ m/s}^2\) upwards.
\(30 text{ m/s}^2\) downwards.

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Mass \(m = 2000 text{ kg}\), Tension \(T = 28000 text{ N}\). Assume \(g = 10 text{ m/s}^2\).\(T - mg = ma implies 28000 - 2000(10) = 2000a\).\(8000 = 2000a implies a = 4 text{ m/s}^2\) upwards.

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