Length of a Second’s Pendulum – Rankers Physics

Uncategorized: Practice Problem & Solution

Time period of a second's pendulum is $2text{ s}$, the approximate length of its string is equal to ($g = 10text{ m/s}^2$)
$2text{ m}$
$1text{ m}$
$frac{1}{3}text{ m}$
$pitext{ m}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Using the formula $T = 2pi sqrt{frac{l}{g}}$, we substitute $T = 2text{ s}$ and $g = 10text{ m/s}^2$: $2 = 2pi sqrt{frac{l}{10}} implies l approx 1text{ m}$.

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