Absorptance, Reflectance and Transmittance Relation – Rankers Physics

Uncategorized: Practice Problem & Solution

If transmittance of a surface is $frac{1}{7}$, reflectance is $frac{1}{8}$, then the absorptance of the surface will be
$frac{1}{9}$
$frac{15}{56}$
$frac{9}{56}$
$frac{41}{56}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Using the relation $a + r + t = 1$, we get $a = 1 - (r + t) = 1 - left(frac{1}{8} + frac{1}{7}right) = 1 - frac{15}{56} = frac{41}{56}$.

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