Rankers Physics

Electromagnetic Induction: Practice Problem & Solution

44. Two coils of self-inductances $2 mH$ and $8 mH$ are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is: (2006)
$8 mH$
$12 mH$
$4 mH$
$16 mH$

Solution Explained:

To solve this problem, we apply the core principles of Electromagnetic Induction. Understanding the underlying formula is key to arriving at the correct answer below:

For complete coupling between two coils, the coupling coefficient is $k = 1$.
The mutual inductance is given by $M = k \sqrt{L_1 L_2}$.
$M = 1 \times \sqrt{2 mH \times 8 mH} = \sqrt{16} = 4 mH$.

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