Rankers Physics

Electric Potential: Practice Problem & Solution

Charge $q_2$ is at the centre of a circular path with radius $r$. Work done in carrying charge $q_1$, once around this equipotential path, would be (1994)
$\frac{1}{4\pi\varepsilon_0} \times \frac{q_1q_2}{r^2}$
$\frac{1}{4\pi\varepsilon_0} \times \frac{q_1q_2}{r}$
Zero
Infinite

Solution Explained:

To solve this problem, we apply the core principles of Electric Potential. Understanding the underlying formula is key to arriving at the correct answer below:

A circular path around a point charge is an equipotential surface because the distance $r$ from the central charge $q_2$ is constant. Since the potential difference between any two points on this path is zero, the work done $W = q\Delta V$ is zero.

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