Rankers Physics

Current Electricity: Practice Problem & Solution

2. A flow of $10^{7}$ electrons per second in a conducting wire constitutes a current of (1994)
$1.6 \times 10^{-12} \text{ A}$
$1.6 \times 10^{26} \text{ A}$
$1.6 \times 10^{-26} \text{ A}$
$1.6 \times 10^{12} \text{ A}$

Solution Explained:

To solve this problem, we apply the core principles of Current Electricity. Understanding the underlying formula is key to arriving at the correct answer below:

Current $I = \frac{q}{t} = \frac{ne}{t}$. Given $\frac{n}{t} = 10^{7} \text{ s}^{-1}$. Thus, $I = 10^{7} \times 1.6 \times 10^{-19} = 1.6 \times 10^{-12} \text{ A}$.

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