Uncategorized: Practice Problem & Solution
50. A cylindrical tube, open at both ends has fundamental frequency $f$ in air. The tube is dipped vertically in water, so that half of it is in water. The fundamental frequency of air column is now: (1997)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
For an open pipe of length $L$, $f = \frac{v}{2L}$. When dipped half in water, it acts as a closed pipe of length $L/2$. Its new fundamental frequency $f' = \frac{v}{4(L/2)} = \frac{v}{2L} = f$.
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