Thermal Physics: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Thermal Physics. Understanding the underlying formula is key to arriving at the correct answer below:

Radiating power $P = \sigma A (T^4 - T_0^4)$. $\frac{P_2}{P_1} = \frac{T_2^4 - T_0^4}{T_1^4 - T_0^4} = \frac{1500^4 - 500^4}{1000^4 - 500^4} = \frac{3^4 - 1^4}{2^4 - 1^4} = \frac{80}{15} = \frac{16}{3}$. $P_2 = \frac{16}{3} \times 60 = 320 \text{ W}$.