Electromagnetic Induction: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Electromagnetic Induction. Understanding the underlying formula is key to arriving at the correct answer below:

Induced emf in the second coil is $e = -M \frac{dI}{dt} = -M \frac{d}{dt}(I_0 \sin \omega t) = -M I_0 \omega \cos \omega t$.
The maximum (peak) value of induced emf is $e_{max} = M I_0 \omega$.
$e_{max} = 0.005 \times 2 \times 100\pi = 0.01 \times 100\pi = \pi V$.