Water Equivalent of Metallic Bar – Rankers Physics

Calorimetry: Practice Problem & Solution

Water equivalent of a metallic bar is \(100\text{ g}\), the energy required to increase its temperature by \(1^\circ\text{C}\) is
\(100\text{ cal}\)
\(1000\text{ cal}\)
\(500\text{ cal}\)
\(50\text{ cal}\)

Solution Explained:

To solve this problem, we apply the core principles of Calorimetry. Understanding the underlying formula is key to arriving at the correct answer below:

Heat required is given by \(Q = W \cdot c \cdot \Delta T\), where \(W\) is the water equivalent. Here, \(Q = 100\text{ g} \times 1\text{ cal/(g }^\circ\text{C)} \times 1^\circ\text{C} = 100\text{ cal}\) of energy.

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