Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

The number of translational degrees of freedom for a diatomic gas is: (1993)
2
3
5
6

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

The center of mass of any molecule can move in three independent directions ($x, y,$ and $z$). Therefore, the translational degrees of freedom for a diatomic gas (or any gas) is always 3.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Column I Column II (A) Total translational kinetic energy (P) $\frac{5}{2} K_B T$ (B) Total rotational kinetic energy (Q) $nRT$ (C) Total kinetic energy per mole (R) $\frac{3}{2} nRT$ (D) Total kinetic energy per molecule (S) $\frac{5}{2} RT$
2. Two moles of an ideal monoatomic gas undergoes an adiabatic process from temperature \(300\text{ K}\) to \(600\text{ K}\). Work done by this ideal gas in the process is
3. The percentage change in length of \( 1\text{ m} \) iron rod if its temperature changes by \( 100^circ\text{C} \) is (\( \alpha \) for iron is \( 2 \times 10^{-5}/^circ\text{C} \))
4. The volume occupied by the molecules contained in $4.5 \text{ kg}$ water at STP, if the intermolecular forces vanish away is: (2022)
5. Assertion (A): A hot body is kept in surrounding. As it cools, its temperature falls from \(80^0 C\) to \(78^0 C\) in a time duration \(t_1\) and from \(50^0 C\) to \(48^0 C\) in time duration \(t_2\). The temperature of surrounding is constant \(20^0 C\), then \(t_1 > t_2\). Reason (R): According to Newton's law of cooling, rate of cooling depends only on the difference of temperature of the body and the surrounding.