Density to Pressure Ratio of Ideal Gas – Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is X. At 110°C this ratio is
\[\frac{10}{110} X\]
\[\frac{283}{383} X\]
\[X\]
\[\frac{383}{283} X\]

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

From ideal gas law, \(P = \frac{\rho RT}{M} \Rightarrow \frac{\rho}{P} = \frac{M}{RT}\). Hence, \(\frac{\rho}{P} \propto \frac{1}{T}\). Thus, the ratio becomes \[X \times \frac{273 + 10}{273 + 110} = X \frac{283}{383}\].

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