Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as: (2020)
$\frac{1}{\sqrt{2} n \pi d^2}$
$\frac{1}{\sqrt{2} n^2 \pi d^2}$
$\frac{1}{\sqrt{2} n^2 \pi^2 d^2}$
$\frac{1}{\sqrt{2} n \pi d}$

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

From the kinetic theory of gases, the mean free path $\lambda$ (the average distance a molecule travels between collisions) is derived as $\lambda = \frac{1}{\sqrt{2} \pi n d^2}$.

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