Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

The value of critical temperature in terms of Van der Waals' constant $a$ and $b$ is given by: (1996)
$T_c = \frac{8a}{27Rb}$
$T_c = \frac{27a}{8Rb}$
$T_c = \frac{a}{2Rb}$
$T_c = \frac{a}{27Rb}$

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

The critical temperature $T_c$ for a real gas obeying the Van der Waals equation is theoretically derived as $T_c = \frac{8a}{27Rb}$, where $a$ and $b$ are the Van der Waals constants.

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