Reverse Bias Resistance of Diode – Rankers Physics

P-N Junction Diode and its applications: Practice Problem & Solution

In a reverse biased diode when the applied voltage changes by \(5 \text{V}\), the current is found to change by \(2 \mu\text{A}\). The reverse bias resistance of the diode is:
\(10^6 \Omega\)
\(2 \times 10^6 \Omega\)
\(5 \times 10^6 \Omega\)
\(2.5 \times 10^6 \Omega\)

Solution Explained:

To solve this problem, we apply the core principles of P-N Junction Diode and its applications. Understanding the underlying formula is key to arriving at the correct answer below:

Reverse resistance is given by \(R = \frac{\Delta V}{\Delta I}\). Substituting the values, \(R = \frac{5 \text{V}}{2 \times 10^{-6} \text{A}} = 2.5 \times 10^6 \Omega\).

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