Rankers Physics

P-N Junction Diode and its applications: Practice Problem & Solution

If a full wave rectifier circuit is operating from $50$ Hz mains, the fundamental frequency in the ripple will be: (2003)
$25$ Hz
$50$ Hz
$70.7$ Hz
$100$ Hz

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of P-N Junction Diode and its applications. Understanding the underlying formula is key to arriving at the correct answer below:

A full-wave rectifier produces two positive output pulses for every single full cycle of the input AC signal. Therefore, the fundamental ripple frequency is twice the input frequency, yielding $2 \times 50 = 100$ Hz.

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