Speed of Centre of Mass of Solid Cylinder on Inclined Plane – Rankers Physics

Rolling on Inclined Plane: Practice Problem & Solution

A solid cylinder of mass $M$ and radius $R$ rolls without slipping down an inclined plane of length $L$ and height $h$. What is the speed of its centre of mass when the cylinder reaches its bottom: (2003)
$\sqrt{2gh}$
$\sqrt{\frac{3}{4}gh}$
$\sqrt{\frac{4}{3}gh}$
$\sqrt{4gh}$

Solution Explained:

To solve this problem, we apply the core principles of Rolling on Inclined Plane. Understanding the underlying formula is key to arriving at the correct answer below:

Using conservation of energy, potential energy equals total kinetic energy: $Mgh = \frac{3}{4}Mv^2$. Solving for velocity gives $v = \sqrt{\frac{4}{3}gh}$.

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