Rotational to Total Kinetic Energy Ratio for Solid Sphere – Rankers Physics

Rotational Motion: Practice Problem & Solution

A solid spherical ball rolls on a table. Ratio of its rotational kinetic energy to total kinetic energy is: (1994)
$\frac{1}{2}$
$\frac{1}{6}$
$\frac{7}{10}$
$\frac{2}{7}$

Solution Explained:

To solve this problem, we apply the core principles of Rotational Motion. Understanding the underlying formula is key to arriving at the correct answer below:

For a solid sphere, $I = \frac{2}{5}MR^2$. Rotational kinetic energy is $\frac{1}{2}Iomega^2 = \frac{1}{5}MR^2\omega^2$ and total kinetic energy is $\frac{7}{10}MR^2\omega^2$. Ratio is $\frac{2}{7}$.

Leave a Reply

Your email address will not be published. Required fields are marked *