Angular SHM and Simple Pendulum: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Angular SHM and Simple Pendulum. Understanding the underlying formula is key to arriving at the correct answer below:

The period of a spring-mass system is given by \( T = 2\pi \sqrt{\frac{m}{k}} \). Immersion in a nonviscous liquid does not change the mass \( m \) or the spring constant \( k \). Hence, the period \( T \) remains unchanged. So (A) is true. Angular frequency is \( \omega = 2\pi / T \), so if \( T \) does not change, \( \omega \) also does not change. So (R) is true and explains (A).