Rankers Physics

Equation of SHM: Practice Problem & Solution

Average velocity of a particle performing SHM in one time period is:
Zero
Aω/2
Aω/2π
2Aω/π

Solution Explained:

To solve this problem, we apply the core principles of Equation of SHM. Understanding the underlying formula is key to arriving at the correct answer below:

As displacement in one time interval is zero. Average velocity is zero.

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Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A particle is executing S.H.M. along a straight line. Its velocities at distances $ x_1 $ and $ x_2 $ from the mean position are $ v_1 $ and $ v_2 $, respectively. Its time period is: (2015)
2. Assertion (A): A SHM may be assumed as composition of many SHM's. Reason (R): Superposition of many SHM's (along same line) of same frequency will be a SHM.  
3. A particle executes simple harmonic oscillation with an amplitude $a$. The period of oscillation is $T$. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is: (2007)
4. Assertion (A): A particle, simultaneously subjected to two simple harmonic motions of same frequency and same amplitude, will perform SHM only if the two SHM’s are in the same direction. Reason (R): A particle, simultaneously subjected to two simple harmonic motions of same frequency and same amplitude, perpendicular to each other the particle can be in uniform circular motion.  
5. If time of mean position from amplitude (extreme) position is $6\text{s}$. Then the frequency of S.H.M. will be: (1998)