Wave Optics - NEET Physics Questions
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Wave Optics

Question 31: moderate

A light has amplitude A and angle between analyser and polariser is 60 degree. Light is transmitted by analyser has amplitude.

1. A√2
2. A/√2
3. √3 A/2
4. A/2
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Question 32: moderate

Two Nicols are oriented with their principal planes making an angle of 60°. The percentage of incident unpolarized light which passes through the system is :

1. 50%
2. 100%
3. 12.5%
4. 37.5%
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Question 33: moderate

The graph showing the dependence of intensity of transmitted light on the angle between polariser and analyser, is :

1.
2.
3.
4.
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Question 34: easy

Spherical wavefronts shown in fig, strike a plane mirror. Reflected wavefronts will be as shown in:

1.
2.
3.
4.
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Question 35: difficult

White light is used to illuminate the two silts in a Young’s double slit experiment. The separation between the slits is b and the screen is at a distance d (> > b) from the slits. At a point on the screen directly in front of one of the slits, certain wavelengths are missing. Some of these missing wavelengths are :

1. \[\lambda=\frac{b^{2}}{d}\]
2. \[\lambda=\frac{2b^{2}}{d}\]
3. \[\lambda=\frac{3b^{2}}{d}\]
4. \[\lambda=\frac{2b^{2}}{3d}\]
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Question 36: easy

The first diffraction minimum due to a single slit diffraction is at θ = 30° for a light of wavelength 5000Å. The width of the slit is :

1. \[5\times 10^{-5} cm\]
2. \[1.0\times 10^{-4} cm\]
3. \[2.5\times 10^{-5} cm\]
4. \[1.25\times 10^{-5} cm\]
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Question 37: easy

The equations of two interferring waves are \(Y_1 = b cos \omega t\) and \(Y_2 = b cos (\omega t+\phi)\) respectively. Destructive interference will take place at the point of observation for the following value of \(\phi\) :–

1.
2. 360°
3. 180°
4. 720°
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For destructive interference to occur, the phase difference between the two interfering waves must be an odd multiple of \(pi\) (i.e., \(180^0\), \(540^0 \), etc.). From the options, \(180^0 \) is correct.

Question 38: easy

Light waves travel in vaccum along the y-axis. Which of the following may represent the wavefront?

1. \(x =\text{ constant}\)
2. \(y =\text{ constant}\)
3. \(z =\text{ constant}\)
4. \(x + y + z =\text{ constant}\)
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Wavefronts are surfaces of constant phase which are perpendicular to the direction of propagation. Since propagation is along the y-axis, the wavefront must be parallel to the x-z plane, represented by \(y =\text{ constant}\).

Question 39: easy

Two polarizers are oriented with transmission planes making an angle of \(45^\circ\) with each other. The percentage of incident unpolarised light that passes through the system is

1. 50%
2. 37.5%
3. 25%
4. 75%
View Answer

An unpolarized light of intensity \(I_0\) becomes \(I_1 = \frac{I_0}{2}\) after passing through the first polarizer. According to Malus's Law, the final intensity is \(I_2 = I_1 cos^2(45^\circ) = \frac{I_0}{2} \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{I_0}{4}\), which corresponds to \(25%\) of the incident intensity.

Question 40: easy

In a diffraction pattern due to a single slit of width \(a\), the first minimum is observed at an angle \(30^\circ\) when light of wavelength \(\lambda\) is incident on the slit. The first secondary maximum is observed at an angle

1. \(sin^{-1}\left(\frac{1}{2}\right)\)
2. \(sin^{-1}\left(\frac{3}{4}\right)\)
3. \(sin^{-1}\left(\frac{1}{4}\right)\)
4. \(sin^{-1}\left(\frac{2}{3}\right)\)
View Answer

For first minimum, \(a sin(30^\circ) = \lambda \Rightarrow a = 2\lambda\). For first secondary maximum, \[a sin\theta = \frac{3}{2}\lambda \Rightarrow sin\theta = \frac{3\lambda}{2(2\lambda)} = \frac{3}{4}\].