Equation of SHM

Practice Questions:

Question 1: difficult

The velocities of a body executing SHM are v₁ and v₂ when the displacements are x1 and x2 respectively. The period is :

View Answer

\[ v= \omega \sqrt{A^{2}-x^{2}} \]

Question 2: difficult

The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t = 4/3 s is :

1. √3/32π² cm/s²

2. -π/32 cm/s²

3. π²/32 cm/s²

4. -√3/32π² cm/s²

View Answer

\[ x= A sin\left( \omega t \right) \]

x= (1cm) sin (2π/8t)= (1 cm ) sin ( π/4t)

v=dx/dt= π/4 cos( π/4t)

a= dv/dt = -(π/4)²sin (π/4t)

a= -(π/4)²sin (π/4×4/3)= -√3/32π² cm/s²

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