What is energy released in the β-decay of \[^{32}P\longrightarrow ^{32}S\] ?

\[\left( Given:atomic masses:-31.97391amu for ^{32}P and 31.97207amu for ^{32}S \right)\]

A beam of fast moving α-particles was directed towards a thin film of gold. The part A’, B’ and C’ of the transmitted and reflected beams corresponding to the incident parts A, B and C of the beam are shown in the adjoining diagram. The number of α-particle in :

Binding energy per nucleon verses mass number curve for nuclei is shown in the figure. W, X, Y and Z are four nuclei indicated on the curve. The process that would release energy is :

The binding energies per nucleon of deuteron \[\left( _{1}H^{2} \right)\] and helium atom \[\left( _{2}He^{4} \right)\] are 1.1 MeV and 7 MeV. If two deuteron atoms react to form a single helium atom, then the energy released is:

Fusion reaction takes place at high temperature because :

A radio isotope ‘X’ with a half life \[1.4\times 10^{9} years\] decays to ‘Y’ which is stable. A sample of the rock from a cave was found to contain ‘X’ and ‘Y’ in the ratio 1 : 7. The age of the rock is :

A common example of β-decay is

\[_{15}P^{32}\longrightarrow _{16}P^{32} + x + y\]

Then x and y stand for :

In radioactive decay process, the negatively charged emitted β – particles are :

Half life of a radio-active substance is 20 minutes. The time between 20% and 80% decay will be :

Initial number of nuclei of a radioactive substance is \[5\times 10^{16}\] and half life is 10 yrs. Find number of nuclei decayed in 5 yrs.